Integrand size = 16, antiderivative size = 146 \[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=-\frac {1}{8} 3^{1+m} b e^{3 a} \left (-\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,-\frac {3 b}{x}\right )+\frac {3}{8} b e^a \left (-\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,-\frac {b}{x}\right )+\frac {3}{8} b e^{-a} \left (\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,\frac {b}{x}\right )-\frac {1}{8} 3^{1+m} b e^{-3 a} \left (\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,\frac {3 b}{x}\right ) \]
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Time = 0.16 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {5458, 3393, 3389, 2212} \[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=-\frac {1}{8} e^{3 a} b 3^{m+1} \left (-\frac {b}{x}\right )^m (e x)^m \Gamma \left (-m-1,-\frac {3 b}{x}\right )+\frac {3}{8} e^a b \left (-\frac {b}{x}\right )^m (e x)^m \Gamma \left (-m-1,-\frac {b}{x}\right )+\frac {3}{8} e^{-a} b \left (\frac {b}{x}\right )^m (e x)^m \Gamma \left (-m-1,\frac {b}{x}\right )-\frac {1}{8} e^{-3 a} b 3^{m+1} \left (\frac {b}{x}\right )^m (e x)^m \Gamma \left (-m-1,\frac {3 b}{x}\right ) \]
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Rule 2212
Rule 3389
Rule 3393
Rule 5458
Rubi steps \begin{align*} \text {integral}& = -\left (\left (\left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int x^{-2-m} \sinh ^3(a+b x) \, dx,x,\frac {1}{x}\right )\right ) \\ & = -\left (\left (i \left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int \left (\frac {3}{4} i x^{-2-m} \sinh (a+b x)-\frac {1}{4} i x^{-2-m} \sinh (3 a+3 b x)\right ) \, dx,x,\frac {1}{x}\right )\right ) \\ & = -\left (\frac {1}{4} \left (\left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int x^{-2-m} \sinh (3 a+3 b x) \, dx,x,\frac {1}{x}\right )\right )+\frac {1}{4} \left (3 \left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int x^{-2-m} \sinh (a+b x) \, dx,x,\frac {1}{x}\right ) \\ & = -\left (\frac {1}{8} \left (\left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int e^{-i (3 i a+3 i b x)} x^{-2-m} \, dx,x,\frac {1}{x}\right )\right )+\frac {1}{8} \left (\left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int e^{i (3 i a+3 i b x)} x^{-2-m} \, dx,x,\frac {1}{x}\right )+\frac {1}{8} \left (3 \left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int e^{-i (i a+i b x)} x^{-2-m} \, dx,x,\frac {1}{x}\right )-\frac {1}{8} \left (3 \left (\frac {1}{x}\right )^m (e x)^m\right ) \text {Subst}\left (\int e^{i (i a+i b x)} x^{-2-m} \, dx,x,\frac {1}{x}\right ) \\ & = -\frac {1}{8} 3^{1+m} b e^{3 a} \left (-\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,-\frac {3 b}{x}\right )+\frac {3}{8} b e^a \left (-\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,-\frac {b}{x}\right )+\frac {3}{8} b e^{-a} \left (\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,\frac {b}{x}\right )-\frac {1}{8} 3^{1+m} b e^{-3 a} \left (\frac {b}{x}\right )^m (e x)^m \Gamma \left (-1-m,\frac {3 b}{x}\right ) \\ \end{align*}
Time = 0.16 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.79 \[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=-\frac {3}{8} b e^{-3 a} (e x)^m \left (3^m e^{6 a} \left (-\frac {b}{x}\right )^m \Gamma \left (-1-m,-\frac {3 b}{x}\right )-e^{4 a} \left (-\frac {b}{x}\right )^m \Gamma \left (-1-m,-\frac {b}{x}\right )+\left (\frac {b}{x}\right )^m \left (-e^{2 a} \Gamma \left (-1-m,\frac {b}{x}\right )+3^m \Gamma \left (-1-m,\frac {3 b}{x}\right )\right )\right ) \]
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\[\int \left (e x \right )^{m} \sinh \left (a +\frac {b}{x}\right )^{3}d x\]
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\[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=\int { \left (e x\right )^{m} \sinh \left (a + \frac {b}{x}\right )^{3} \,d x } \]
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\[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=\int \left (e x\right )^{m} \sinh ^{3}{\left (a + \frac {b}{x} \right )}\, dx \]
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\[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=\int { \left (e x\right )^{m} \sinh \left (a + \frac {b}{x}\right )^{3} \,d x } \]
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\[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=\int { \left (e x\right )^{m} \sinh \left (a + \frac {b}{x}\right )^{3} \,d x } \]
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Timed out. \[ \int (e x)^m \sinh ^3\left (a+\frac {b}{x}\right ) \, dx=\int {\mathrm {sinh}\left (a+\frac {b}{x}\right )}^3\,{\left (e\,x\right )}^m \,d x \]
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